Question

Use the quadratic formula to find the roots of the equation. Round to tenths if necessary. x2 - 6x + 2 = 0
A.{0.4, 5.6}
B.{0.5, 4.8}
C.{1.4, 2.4}
D.no real number solution

Answer 1

someone please help me with this i'm very confused

Answer 2

hint... use this formula:

\[\LARGE {x_{1/2}} = \frac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}\]

and you have..a=1 b=-6 c=2

Answer 3

\[\LARGE \Delta = {b^2} - 4ac\]

\[\LARGE \begin{array}{l}\Delta > 0\;\;\;\;{\rm{ two solutions}}{\rm{.}}\\\Delta {\rm{ = 0\;\;\;\; one solution}}{\rm{.}}\\\Delta {\rm{ < 0 \;\;\;\; no solution}}{\rm{.}}\end{array}\]

Answer 4

that's what your saying?