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OpenStudy (anonymous):
How many grams of water can be produced when 8.73 moles of benzene (C6H6) react with excess oxygen? Unbalanced equation: C6H6 + O2 → CO2 + H2O
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OpenStudy (mos1635):
C6H6 + 15/2 O2 →6 CO2 + 3H2O 1mole...................................3 mole 8.73 mole..............................x=? mass=Mr*mole Mr(water)=18 m=.....
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