Question

Solve 64^(2-x)=4^(4x)

Answer 1

http://www.wolframalpha.com/input/?i=64%5E%282-x%29%3D4%5E%284x%29

Answer 2

\[\large64=4^4\]so we have\[64^{2-x}=4^{4x}\]\[(4^4)^{2-x}=4^{4x}\]\[4^{8-4x}=4^{4x}\]do you think you can solve it now?

Answer 3

8-4x= 4x
add 4x to each sides

Answer 4

(4^4)^(2-x) =4^(4x)
4^(8-4x) =4^(4x)
8-4x=4x
8=8x
x=8/8
x=1