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whats the added # to make a perfect square: k^2+11k
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121/4: (k + 11/2)(k + 11/2) = k^2 + 11k + 121/4
@cwrw238 can you break it down for me?
(k + 11/2)(k + 11/2 = k^2 + 11/2* k + 11/2 * k + 11/2 * 11/2 = k^2 + 11k + 121/4
you need to divide the 11k by 2 and square the result
- * sorry : square the 11/2
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\[11/2^{2} is 2.75 or 11/4 ??\]
no its (11/2)^2 = 11^2 / 2^2 = 121/4
so the # the make a perfect square is 121/4 ??
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