Question

The coordinates of Trapezoid EFGH are E(4, 8), F(1, 2), G(6, 1), and H(8,8). The image of EFGH under dilation is E’F’G’H’.

If the coordinates of vertex E’ are (1, 2), what are the coordinates of vertex H’?
(2, 8)
(5, 6)
(2, 2)
(4, 8)

Answer 1

It looks like you just have to multiply the coordinates of H by the same factor that reduces E(4,8) to E'(1,2)