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Mathematics 13 Online
OpenStudy (anonymous):

what is the value of a

OpenStudy (slaaibak):

must be 10

OpenStudy (slaaibak):

\[x^{1 \over 3} + 1 = 0\]

OpenStudy (anonymous):

what's the problem with "a" in it?

OpenStudy (anonymous):

so the formula is P = IR ohm's law?

OpenStudy (anonymous):

P=IV V=IR P=I^2*R i think that last one is the one you want

OpenStudy (anonymous):

so I=sqrt(P/R)

OpenStudy (anonymous):

y=k/x 8=k/3 k=24 so y=24/x

OpenStudy (anonymous):

now substitute and solve

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