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Mathematics 6 Online
OpenStudy (anonymous):

Find the derivative of y=2sinxcosx.

OpenStudy (anonymous):

look, 2sinxcosx is an expand for the rule ,sin2x so if u take sin2x and make derivative then : it will be (cos2x)(2)

OpenStudy (anonymous):

yep...

OpenStudy (anonymous):

would the anwer be the same if i got 2cos^2x-2sin^2x

OpenStudy (anonymous):

find what's cos2x = ... there's an identity....

OpenStudy (anonymous):

yeah it is the same

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