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OpenStudy (anonymous):
Find the derivative of y=2sinxcosx.
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OpenStudy (anonymous):
look, 2sinxcosx is an expand for the rule ,sin2x so if u take sin2x and make derivative then : it will be (cos2x)(2)
OpenStudy (anonymous):
yep...
OpenStudy (anonymous):
would the anwer be the same if i got 2cos^2x-2sin^2x
OpenStudy (anonymous):
find what's cos2x = ... there's an identity....
OpenStudy (anonymous):
yeah it is the same
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