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Help with law of sines triangle problem (pic incoming)
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How about we find angle B first?
I just don't get how to start off...
\[\frac{\sin B}{10}=\frac{\sin 45}{8.2}\]
Oh okay....I see what I did. I wrote the equation incorrectly. So I calculated it and got sinx=.86 and then took arcsin(.86) and got 59.4 roughly for angle B'. Then I took that info and used it to find the other angle and got 120.4. Is that right?
That's where the ambiguity comes in. The angle could be 59 or 180-59.6 or 120.4
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