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OpenStudy (anonymous):
Verify that each equation is an identity 1+sinA-cos2A ------------- = tanA cosA+sin2A
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OpenStudy (anonymous):
anyone?
OpenStudy (cwrw238):
1 + sinA - cos2A = 1 + sinA - (1 - 2sin^2A) = 2sin^2A + sin A = sinA(2sinA + 1) cosA + sin 2A = cosA + 2sinAcosA = cosA(2sinA + 1) sinA(2sinA + 1) ------------- = sinA / cosA = tan A cosA(2sinA + 1) this proves the identity
OpenStudy (anonymous):
thank you!!!!
OpenStudy (cwrw238):
yw
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