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the measure of the supplemt of an angle is 40degree less than 6 times the measure of its complement . Find the angle . ( use algebra) How to do this problem ?? Show steps please !! >< All answer gets medals !!
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Let the angle be x We are given the supplement of the angle (180-x) is 40 less than six times its complement (90-x) so we have \[(180-x) =6(90-x)-40\] so we get now \[180-x=540-6x-40\] Can you solve now????
@MetalPencil did you understand? Can you do it now?
yup !!! thanks a LOT :)
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