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Solve for x: x=xe^(3-x).
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take the natural log of both sides.
And, I forget log laws.
Can anyone help me? 3.41 x 1,3019234 divided by 12347 x 8 + your age - 1804351 x 235-135425 squaredx 10 to the fifth power + 1- 1243818723847
Post a new question instead of posting here please, Fweaa.
\[\LARGE x=x\cdot e^{3-x}\] \[\LARGE \frac xx = e^{3-x}\] \[\LARGE 1= e^{3-x}\] \[\LARGE 1=a^x \quad \Longleftrightarrow x=0\]
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so... \[\LARGE 3-x=0\] \[\LARGE -x=0-3\] \[\LARGE -x=-3\] \[\LARGE x=3\]
yes ... @bmp
Ah, sorry, mate. I thought that you had ended your proof and made a minor mistake at the very end. My bad. :-)
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