Question

y=1/3x^2-4x+6

Answer 1

Solve for x?

Answer 2

im suposed to graph it

Answer 3

Ok. Well automatically, you can tell that it is a parabola (quadratic) right?

Quadratics are more easily graphed when you have the equation in quadratic form:
y=a(x-h)^2 +k

So you will want to convert the above equation to this form. They you can take the vertex and y intercept from the form

Answer 4

i forgot the step after finding the vertex and the formula you use to do it

Answer 5

The vertex is the point (h,k)

Answer 6

im pretty sure the vertex is(6,-6)

Answer 7

i used the formula ...x=-(b)/2(a)

Answer 8

That formula works too :) That will give you the x value that is the axis of symmetry. In the case you are doing, the vertex will be ( [-b/2a], f([-b/2a]))

Answer 9

its so confusing

Answer 10

i dont know what you just wrote, its like a foriegn language

Answer 11

...

Answer 12

OH! sorry! um what I wrote represents the coordinate pair of the vertex. -b/2a is the x value.

f(-b/2a) is the y value that coresponds with the above x value

Answer 13

i got 2.67

Answer 14

- for you can solve it you need make it equal zero

- so 1/3 x^2 -4x +6 =0 multiply both sides by 3
3x^2
---- -12x +18 =0
3

x^2 -12x +18 =0
D =144 - 4*1*18 =144 -72 =72

x_1,2= (12+/- sqrt72)/2 =(12+/- sqrt(9*4*2))/2 =(12+/- 6sqrt2)/2 =
=2(6+/-3sqrt2)/2 =6+/-3sqrt2

x_1,2=6+/-3sqrt2