Solve the following system of equations.

x + y – 4z = –7
2x + 3y – 3z = –6
2x + 2y – z = 0

Question

Solve the following system of equations.

x + y – 4z = –7
2x + 3y – 3z = –6
2x + 2y – z = 0

jhonyy9 · Answer

- subtract 3rd from second

2x +3y -3z = -6
2x +2y -z = 0
---------------
 0     y  -2z = -6

 - multiply first by -2 and assum by second

-2x -2y +8z = 14
  2x +3y -3z = -6
----------------
  0    y  +5z = 8

y-2z=-6
y+5z=8
---------- subtract second from first
 0 -7z =-14
z=2

y+5z=8
y+5*2=8
y+10=8
y=-2

z=2
y=-2

 x+y -4z=-7
x +(-2) -4(2) = -7
x-2-8=-7
x-10=-7
x=3

x=3
y=-2
z=2

anonymous · Answer

I hadnt realized you answered thank you so much:D