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(1 pt) From a group of 8 women and 6 men a committee consisting of 4 men and 4 women is to be formed. How many different committees are possible if (a) 2 of the men refuse to serve together? answer: (a) 2 of the women refuse to serve together? answer: (a) 1 man and 1 woman refuse to serve together? answer:
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im so mad right now, i forgot. but the trick was something like to instead of the normal 8 over 4, 6 over 4, to subtract one from the males, this makes them not be able to match and then you didnt account for that male in any combo, so you will add all the combos that only that one male can make. something like that, sorry
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