Question

How many three symbol codes using the digits 2 through 9 are possible if no repetitions are allowed?

Answer 1

Of the possible digits, \(2, 3, 4, 5, 6, 7, 8, 9\) there are 8 total numbers. Since they can't be repeated, you'll have 8 choices for the first spot, only 7 for the second spot, and only 6 for the third spot.

Hence, \[8*7*6=336\]Possible codes

Answer 2

Thanks ;))

Answer 3

You're welcome.