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Mathematics 9 Online
OpenStudy (anonymous):

Find the slope of the tangent line to the curve √4x+1y + √2xy = 6.06 @ the point (3,1) I got this (-1-sqrt(2) sqrt(x) y)/(sqrt(x) (1+sqrt(2) x)), then I plugged in the values 3 and 1 the answer is -0.379877994777674 But for some reason I still got it wrong I guess not sure Any help?

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