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OpenStudy (anonymous):
how would you solve sinx=cosx
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OpenStudy (anonymous):
divide both sides by cosx so you'll have tanx = 1
OpenStudy (anonymous):
okay thank you:)
OpenStudy (anonymous):
use the trig identity sin^2x + cos^2x = 1, and substitute your sin or cos value.
OpenStudy (anonymous):
yw... btw... did it ask for the general solution? or just solutions between 0, 2pi?
OpenStudy (anonymous):
General
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OpenStudy (anonymous):
you know how to write it out?
OpenStudy (anonymous):
Yeaaa thanks :)
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