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Simplify. b3·b-5·b11 A) b9 B) b15 C) b19 D) b-165
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\[b^3.b^{-5}.b^{11}\]?
you mean (b^3)(b^-5)(b^11) ?
if so .... add the powers
\[\huge x^m \times x^n = x^{m+n}\] Use this !
soo what is it
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What did you get ?
its A. b^9
\[\large b^{3+(-5)+11}= answer \]
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