Is my answer correct?
Question: Find the exact value of the following trig function:
cos (-150deegrees)
answer:
Theta terminates in Quadrant III.
Reference angle is 30degrees
cos = negative in Quadrant III
cos (-150) = -cos (30) = Square root of 3/2
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OpenStudy (anonymous):
right
OpenStudy (anonymous):
Correct
OpenStudy (angela210793):
tht's right
OpenStudy (anonymous):
I have a q, If at the end its -cos (30) shouldnt my answer be influenced and become - Square root of 3/2? Or it doesnt matter?
OpenStudy (anonymous):
\[\cos (-\theta) = \cos \theta \]
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OpenStudy (anonymous):
Please dont leave, I have one more question:
OpenStudy (anonymous):
to find exact value of tan (225)
is my answer correct?
theta terminates in Q3
R. angle is 45
tan = positive in Q3
tan(225) = tan(45) = 1
OpenStudy (experimentx):
tan(180+45)
OpenStudy (experimentx):
whenever there is 180 turn function remains same, and or 90 function changes.
OpenStudy (angela210793):
i wish u knew albanian -_- i'd have explained these to u -_-
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OpenStudy (anonymous):
Wait, so 1 is wrong?
OpenStudy (anonymous):
so exact balue of tan(225) is not 1?
OpenStudy (anonymous):
*value
OpenStudy (anonymous):
1 is right!
OpenStudy (anonymous):
Oh. lol. Ok thank you guys so much! as usual you guys ROCK!!:)