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The area of triangle ABC is equal to 120, point B lies on the segment BC, that BD: CD = 1: 2, the bisector of BK crossed of the line of AD in the point L. Find the area of a quadrilateral if KLDC AK: KC = 3:1.
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>>point B lies on the segment BC Did you mean to say point D lies on segmetn BC?
>>>the bisector of BK Where is point K. Do you have a diagram you could draw or upload?
AD - simply refer to
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