Question

sigma ((7^(n)/(9^(n)(n!)) this is for n going to infinity from 0.
find the sum of the series.

Answer 1

Latex please.

Answer 2

\[\sum_{0}^{infiniti} ((7^{n}))/9^{n}(n!))\]

Answer 3

looks like e^(7/9)

Answer 4

use the ratio test

Answer 5

http://tutorial.math.lamar.edu/Classes/CalcII/RatioTest.aspx

Answer 6

limit n->inf ((7/9)^(n+1)/(n+1)!)/((7/9)^n/(n!))

limit n->inf ((7/9)^(1)/(n+1)!)/(1/(n!))

limit n->inf ((7/9)/(n+1))

= 0 < 1