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the solution set sqrt3x+16=x+2 is (only 3x+16 is squared)
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\[\sqrt{3x+16}=x+2\]??
square both sides get \[3x+16=x^2+4x+4\] then solve \[x^2+x-12=0\] \[(x-3)(x+4)=0\] \[x=3\] or \[x=-4\] then check the answers because only one will work
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