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Factor: 81x^2-49
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\[\LARGE 81=9^2 \quad \quad and \quad \quad 49=7^2\] so... \[\LARGE 9^2x^2-7^2=(9x)^2-7^2\] now use this formula: \[\LARGE a^2-b^2=(a-b)(a+b)\] to get... \[\LARGE (9x)^2-7^2=(9x-7)(9x+7)\]
This is the same kind of problem as before.
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