Mathematics
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OpenStudy (anonymous):
what is the square root of 75x^2y
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OpenStudy (anonymous):
ty
OpenStudy (saifoo.khan):
Factor 75.
OpenStudy (anonymous):
hay how do u fined where the answer is ?
OpenStudy (saifoo.khan):
\[\sqrt{75} = \sqrt{5 \times 5 \times 3} = 5 \sqrt3\]
OpenStudy (anonymous):
ooooo ty can u help me with one more answer?
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OpenStudy (saifoo.khan):
Therefore,
\[5x \sqrt{3y}\]
OpenStudy (saifoo.khan):
Sure. Throw it.
OpenStudy (anonymous):
what is 147m^3n^3
OpenStudy (saifoo.khan):
Is there a radical or something?
OpenStudy (anonymous):
no they just want us to find out what the square root of the number is and put the m and nsomewhere im having some troulbe understanding it really
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OpenStudy (saifoo.khan):
Can you factor 147?
OpenStudy (anonymous):
147 can be factored into 3 by 49
OpenStudy (saifoo.khan):
perfect.
OpenStudy (saifoo.khan):
\[\sqrt{147} = \sqrt{3 \times 49} = \sqrt{3 \times 7 \times 7} = 7 \sqrt3\]
OpenStudy (anonymous):
now what do i do with the m^3 and N^3
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OpenStudy (saifoo.khan):
Look,
Break it into exponent two.
\[\Large \sqrt{m^3} = \sqrt{m^2 \times m} = m \sqrt m\]
OpenStudy (saifoo.khan):
Same as the case with n^3
OpenStudy (anonymous):
so it would be 7mn square root and 3mn?
OpenStudy (saifoo.khan):
Omg! you are a guru in this!
OpenStudy (anonymous):
ty so much by the way i gtg
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OpenStudy (saifoo.khan):
Welcome.
No worries.
Be back soon! ^_^