what is equivalent to log 8 35 rounded to three decimal places
Do you have a calculator that can do logs?
yes how do i plug that in
Assuming the question is \[\large \log_{8}{35}\]Plug in:\[\Large {\log 35 \over \log 8}\]Where \(\log\) is the log base 10.
i got 1.70976100.....
would my answer be 1.710
??
That is also what I'm getting. Sorry I was gone for a few minutes there.
its fine! how would i answer thiss? what is equivalent to log 25 125 ?
Here's a nice easy way to see this. Since \[\Large \log_b(a) = x\;\;\;\; \Longrightarrow b^x =a\]So we want some number \(x\) s.t. \[\large 25^x=125\]To solve this, write \(25=5^2\) and \(125=5^3\). Thus, we have \[(5^2)^x =5^{2x}=5^3\]So \(2x=3\). Solving for \(x\) we have \(x=1.5\)
Alternatively, calculate \[\log 125 \over \log25\]
g2g now, good luck.
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