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Someone please help me with this, I have no idea how to do it. If sin theta =7/8 for pi/2 < or = theta < or = pi and cos alpha= - 5/6 for pi < or = pi < or = alpha < or = 3pi/ 2 find the value of cos ( theta - alpha ) PLEASE HELP ME!
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I'm going to use x and y for theta and alpha.
\[\cos (x-y)=\cos x \cos y+\sin x \sin y\]
I see that theta (I'm using x) is in the second quadrant.|dw:1334024155805:dw|
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