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Mathematics 14 Online
OpenStudy (anonymous):

SEE ATTACHMENT ! HELP 6. Solve for x. (1 point) 1 2 3

OpenStudy (anonymous):

jimthompson5910 (jim_thompson5910):

sqrt(2x+3) = sqrt(6x-1) (sqrt(2x+3))^2 = (sqrt(6x-1))^2 2x+3 = 6x - 1 2x+3-3 = 6x - 1-3 2x = 6x-4 2x-6x = 6x-4-6x -4x = -4 -4x/(-4) = -4/(-4) x = 1 So the solution is x = 1

OpenStudy (anonymous):

7. Solve for b. (1 point) 2 3

jimthompson5910 (jim_thompson5910):

sqrt( (b^4)/25 ) = 4 (sqrt( (b^4)/25 ))^2 = 4^2 (b^4)/25 = 16 ((b^4)/25)*25 = 16*25 b^4 = 400 sqrt(b^4) = sqrt(400) b^2 = 20 sqrt(b^2) = +-sqrt(20) b = +-2*sqrt(5) So the answer is the second choice

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