Question

Need help fast!!!!!!
The perimeter of a rectangular concrete slab is 114 feet and its area is 702 square feet. Find the dimensions of the rectangle.

Part a.

Using l for the length of the rectangle, write an expression for the width of the rectangle in terms of l. (Hint: Solve the formula for w.) Show your work.

Part b.

Write a quadratic equation using l, the expression you found in part (a), and the area of the slab.

Part c.

Solve the quadratic equation. Use the two solutions to find the dimensions of the rectangle.

Answer 1

L * W = area
W = area/L = 702/L

2L + 2w = 114
2L + 2(702/L) = 114
2L^2 + 1404 = 114L
2L^2 - 114L + 1404 = 0

Solve using quadratic formula.

Answer 2

well for the perimeter
Part (a)
114 = 2l + 2w rewrite the equation is w = 57 - l


Part (b)
Area 702 = lw use the above substitution for w

702 = l( 57 - l)

703 + 75l - l^2

or

\[l^2 - 57l + 702 = 0\]

Part (c)

\[l^2 - 57l + 702 = ( l - 18)(l - 39)\]

then (l - 18)(l - 39) = 0

when l = 18 or 39

Rectangle 1 length = 18, width = 39