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Given that y=0 when x=1, solve the differential equation \[xy{dy \over dx}= y^2 +4\]obtaining an expression for y^2 in terms of x.
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Not sure, but can you see if you can help me to solve?
So, can you show how?
what i typed before was mistake ... didn't realize that y was in wrong place. |dw:1334048924486:dw|
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