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cos(x-pi/3)=-1/2
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Find x..
let first solution be alpha \[\alpha -\frac{\pi}{3}= \cos^{-1}\frac{-1}{2} = \frac{2\pi}{3}\] \[\alpha = 2\pi\] general solution for integer n: \[x = 2\pi n +\pi = (2n+1)\pi \]
i think i did it right..
cos(x-pi/3)=-1/2 x - pi/3 = 2pi/3 or x - pi/3 =4pi/3 x = 2pi/3 + pi/3 or x = 4pi/3 + pi/3 x = pi or x = 5pi/3
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shoot i missed a solution
calm.....
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