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Mathematics 16 Online
OpenStudy (anonymous):

5x2-87x+378=0

OpenStudy (anonymous):

use quadratic formula

OpenStudy (anonymous):

(x_9)(5x-42)

OpenStudy (anonymous):

please explain detailed

OpenStudy (anonymous):

i get (x-9)(5x-42)=0 after step

OpenStudy (anonymous):

factorise 5x2-87x+378 u will get: (x-9)(5x-42) so, (x-9)(5x-42)=0 so, one of these terms has to be 0 so, x=9 or 42/5

OpenStudy (anonymous):

x=9 or 42/5

OpenStudy (anonymous):

Thank you very much for the answer to all

OpenStudy (hoblos):

5x2-87x+378=0 5x2 - 42x - 45x + 378 =0 x(5x-42) - 9(5x-42) =0 (5x-42)(x-9) =0 so 5x-42=0 or x-9=0 x=42/5 x=9

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