Question

16^-3/4 equals?

Answer 1

\[\LARGE \left(16\right)^{-\frac34}=\left(4^2\right)^{-\frac34}=\left(4\right)^{-\frac{3\cdot 2}{ 4}}\]
\[\ \LARGE =\left(4\right)^{-\frac{3}{ 2}}=\left(2^2\right)^{-\frac{3}{ 2}}=2^{-3} \]
\[\LARGE =\frac{1}{2^3}=\frac18 \]