Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

the perimeter of a rectangle is 36 ft, and the area of the rectangle is 56 ft^2 . fine the dimensions of the rectangle ? length : width :

OpenStudy (ujjwal):

2(l+b)=36.....(1) l*b=56......(2) solving above two eqns, l=14 b=4

OpenStudy (anonymous):

this is the final answer ?

OpenStudy (ujjwal):

yep length= 14 ft breadth= 4 ft However you can interchange their values.. they are arbitarily chosen.. bt the general assumption is to keep lenght longer so length= 14

OpenStudy (anonymous):

the length of a rectangle is 1 yd less than twice its width, and the area of the rectangle is 55 yd^2. find the dimensions length : width:

OpenStudy (anonymous):

.

OpenStudy (ujjwal):

length=6.9 and breadth=7.9 approx

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!