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OpenStudy (anonymous):
a box of chocolates contains 12 chocolates with nuts and 24 24 with out nuts. Determine the probability of choosing 2 chocolates with nuts in a row without replacement
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OpenStudy (anonymous):
\[\frac{12}{36}*\frac{11}{35}\\ \frac{1}{3}*\frac{11}{35}\\ =\frac{11}{105}\]
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