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OpenStudy (anonymous):
Calculate the number of moles of HCl used in your experiment....the balanced equation will be provided in a comment I will make. 0.0139 mol CaCO3 40.0mL HCl Initial Mass of CaCO3 1.39 grams
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OpenStudy (anonymous):
\[CaCO3 + 2HCl \rightarrow CaCl2 + H2O + CO2\]
OpenStudy (anonymous):
to tired, LOL JK. I dunno
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