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The sum of three consecutive integers is 252. Find the integers. Define the variables and set up an equation.
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let the first integer be x the next two consecutive integers would be (x+1) and (x+2) The sum of the three is 252 so x+x+1+x+2=252 3x+3=252 3x=252-3 3x=249 x=249/3 x=83 Since you have found the first integer...what are the two numbers that come after 83?
x+x+1+x+2 =252 solve for x
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