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if f(x)=3x^2/2x and g(x)=3x^2/4x, find f(x)÷g(x) a. 9x^2/8 b.x c. 2 d. 1/2
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C. you get \[(3x^2)(4x)/(2x)(3x^2)\] the (3x^2)'s cancel leaving 4x/2x then the x's cancel leaving 4/2 which =2
(3x^2/2x)(4x/3x^2) = 2
omg i got it right! thanks :_)
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