Question

Find equation of circle tangent to 3x-4y-4=0 at (0,-1) containing the point (-1,-8)

Answer 1

is 0,-1 center??

Answer 2

the line would then be a secant line in that case

Answer 3

so (0,-1) not center

Answer 4

must be another point.

Answer 5

All I know is that the center is the perpendicular bisector of the line joining (0,-1) and (-1,-8) T_T

Answer 6

Nvm I got it xD (x-3)^2 + (y+5)^2= 25