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Mathematics 7 Online
OpenStudy (anonymous):

ln (x/y)

OpenStudy (anonymous):

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OpenStudy (anonymous):

is this just ln x - ln y?

OpenStudy (anonymous):

Yup

OpenStudy (anonymous):

\[\ln(xy) = \ln(x) + \ln(y)\]\[\ln({x \over y}) = \ln(x) - \ln(y) \]\[\ln(x^y) = y \ln(x)\]

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