Question

How would you simplify this?

sinTheta cos theta /tan theta

Answer 1

\[\large \frac{\sin \theta \cos \theta}{ \frac{\sin \theta }{\cos \theta }}\]

Answer 2

btw, we are doing identities right now.

Answer 3

\[{\sin \theta \cos \theta \over \tan \theta} = {\sin \theta \cos \theta \over {\sin \theta \over \cos \theta}}\]

Answer 4

since \[\tan \theta = \frac{\sin \theta }{\cos \theta }\]

Answer 5

\[\large \frac{\sin \theta \cos \theta*\cos \theta }{\sin \theta }= \cos^2 \theta \]

Answer 6

oh so you factor out the sin theta

Answer 7

Yes \[\large \frac{\cancel{\sin \theta} \cos \theta*\cos \theta }{\cancel {\sin \theta }}= \cos^2 \theta\]

Answer 8

Ok. that makes sense. Thank you:)

Answer 9

Anytime ^_^