Question

Solve the system using substitution:
x^2+y^2=32
y=x

How do i do this?

Answer 1

substitute x in for y
then add together to get 2x^2 = 32
solve from there

Answer 2

substitute y=x in the first equation
x^2+x^2=32
2x^2=32
x^2=16
x=(plus or minus)4=y

Answer 3

Multiple choice answers are: (-4,-4) (-4,4) (4,-4) (4,4) which one would it be?

Answer 4

(-4,-4) and (4,4)

Answer 5

Thank you so much. What about:
x^2-y+5=0
x-y+5=0