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The sum of three integers is 136. The second number is three times the first. The sum of the first two numbers equals the third. Find the three integers.
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a + b + c = 136 3a = b a + b = c solve from there
Yeah ive gotten that far i just dont know what to do from there..
substitute 3a into a + b = c to get 4a = c then substitute for b & c with the equations you've got
into the first
Okay thanks!
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