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anti derivative of 3/x?
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=integral 3*1/x = 3 ln x
actually 3 ln |x|
so with or without absolute sign?
with
can any of you help me onsome differential equation problems?
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idk but ill give it a shot
solve the initial value problem of y'=xe^y-2e^y if y(0)=0
already confused sorry cant help you
thats ok
\[y'=xe^y-2e^y \] \[y'=e^y(x-2)\] \[\frac{dy}{dx}=e^y(x-2)\] \[dy=e^y(x-2)dx\] \[\frac{dy}{e^y}=(x-2)dx\] Integrate both sides! :)
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\[\int\limits_{}^{}e^{-y} dy =\int\limits_{}^{}(x-2)dx\]
\[-e^{-y}=\frac{x^2}{2}-2x+C\]
Now apply initial condition to find C
replace x with 0 and replace y with 0 and solve for C
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