Question

Eigenvectors of [-6 -2;4 -2]
So the values are -4+-2i, then figuring out the vectors, lambda = -4 -2i...
= [-2 +2i -2; 4 2+2i]
and I get stuck as in row reduced form there are 2 rows instead of 1...

Answer 1

is that a 2x2 matrix to start with?

Answer 2

a-L b
c d-L

RREFs to


1 b/(a-L)
0 0

therefore your eugene vector = <-b/(a-L) , 1>

Answer 3

yep I've seen what you've done, cheers!

time for some sleep I think.....