Eigenvectors of [-6 -2;4 -2]
So the values are -4+-2i, then figuring out the vectors, lambda = -4 -2i...
= [-2 +2i -2; 4 2+2i]
and I get stuck as in row reduced form there are 2 rows instead of 1...

Question

Eigenvectors of [-6 -2;4 -2]
So the values are -4+-2i, then figuring out the vectors, lambda = -4 -2i...
= [-2 +2i   -2; 4      2+2i]
and I get stuck as in row reduced form there are 2 rows instead of 1...

amistre64 · Answer

is that a 2x2 matrix to start with?

amistre64 · Answer

a-L  b    
 c   d-L

RREFs to


1  b/(a-L)
0      0

therefore  your eugene vector = <-b/(a-L) , 1>

anonymous · Answer

yep I've seen what you've done, cheers!

time for some sleep I think.....