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Mathematics 20 Online
OpenStudy (anonymous):

sinx/sinx-cosx ....solution

OpenStudy (apoorvk):

solution means, solve for x?

OpenStudy (anonymous):

apoorvk

OpenStudy (anonymous):

wrong itz

OpenStudy (apoorvk):

IITJEE AIR-12 is asking this question. What are we? What do you want to do? Integrate??

OpenStudy (anonymous):

ya u know dat???????? kl mene aye hi question phuchta

OpenStudy (anonymous):

sin(x)/(sinx - cosx)

OpenStudy (anonymous):

= sin(x)/(sinx - cosx) * (1/sinx)/(1/sinx)

OpenStudy (anonymous):

= sin(x)/sin(x) / ((sinx - cosx)/sin(x))

OpenStudy (anonymous):

1 / (sin(x)/sin(x) - cos(x)/sin(x))

OpenStudy (anonymous):

1 / (1 - cot x)

OpenStudy (anonymous):

did u get it or sumthg elz i do

OpenStudy (anonymous):

first of all, you know that "cot x = 1/tan x" and "tan x = sin x/cos x"

OpenStudy (anonymous):

So divide both the numerator and denominator in the left side by sin x, and you get

OpenStudy (anonymous):

(sinx/sinx)/(sinx/sinx - cosx/sinx) =

OpenStudy (anonymous):

1/ (1-1/tanx)

OpenStudy (anonymous):

= 1/ (1-cotx).

OpenStudy (anonymous):

gurvinder r yo there?

OpenStudy (anonymous):

ok thnx apoorvk ....mujhe malum hai

OpenStudy (anonymous):

m saying sumthg..is it right?

OpenStudy (apoorvk):

shruti stop wasting you time over his questions, its no use.

OpenStudy (anonymous):

ok what is ur answer ok.....i can do better den u?? hhaha lol

OpenStudy (anonymous):

ya apoorvk r u der????? o sorry shruti

OpenStudy (anonymous):

apoorvk my next question is coming plzzz so help

OpenStudy (anonymous):

ohh its okay..

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

:D:D

OpenStudy (anonymous):

Hehehhehe

OpenStudy (anonymous):

sa***e IIT ka topper aur trig. identities pooch raha hai *someonehadtosayit*

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