Mathematics
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OpenStudy (anonymous):
sinx/sinx-cosx ....solution
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OpenStudy (apoorvk):
solution means, solve for x?
OpenStudy (anonymous):
apoorvk
OpenStudy (anonymous):
wrong itz
OpenStudy (apoorvk):
IITJEE AIR-12 is asking this question. What are we?
What do you want to do? Integrate??
OpenStudy (anonymous):
ya u know dat???????? kl mene aye hi question phuchta
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OpenStudy (anonymous):
sin(x)/(sinx - cosx)
OpenStudy (anonymous):
= sin(x)/(sinx - cosx) * (1/sinx)/(1/sinx)
OpenStudy (anonymous):
= sin(x)/sin(x) / ((sinx - cosx)/sin(x))
OpenStudy (anonymous):
1 / (sin(x)/sin(x) - cos(x)/sin(x))
OpenStudy (anonymous):
1 / (1 - cot x)
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OpenStudy (anonymous):
did u get it or sumthg elz i do
OpenStudy (anonymous):
first of all, you know that "cot x = 1/tan x" and "tan x = sin x/cos x"
OpenStudy (anonymous):
So divide both the numerator and denominator in the left side by sin x, and you get
OpenStudy (anonymous):
(sinx/sinx)/(sinx/sinx - cosx/sinx) =
OpenStudy (anonymous):
1/ (1-1/tanx)
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OpenStudy (anonymous):
= 1/ (1-cotx).
OpenStudy (anonymous):
gurvinder r yo there?
OpenStudy (anonymous):
ok thnx apoorvk ....mujhe malum hai
OpenStudy (anonymous):
m saying sumthg..is it right?
OpenStudy (apoorvk):
shruti stop wasting you time over his questions, its no use.
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OpenStudy (anonymous):
ok what is ur answer ok.....i can do better den u?? hhaha lol
OpenStudy (anonymous):
ya apoorvk r u der????? o sorry shruti
OpenStudy (anonymous):
apoorvk my next question is coming plzzz so help
OpenStudy (anonymous):
ohh its okay..
OpenStudy (anonymous):
lol
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OpenStudy (anonymous):
:D:D
OpenStudy (anonymous):
Hehehhehe
OpenStudy (anonymous):
sa***e IIT ka topper aur trig. identities pooch raha hai
*someonehadtosayit*