Question

Solve:
4x2 + 12x = 0
a) x = 0, -3
b) x = 3
c) x = 0, 3
d) x = -3

Answer 1

a

Answer 2

\[4x^2+12x = 0\]
You can divide both sides by 4 and get
\[{4\over4} x^2 + {12\over4}x={0\over4}\]\[x^2+3x=0\]\[x(x+3)=0\] wich is true only if x is equal to 0 or x is equal to -3

Answer 3

a is the answer