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Mathematics 13 Online
OpenStudy (anonymous):

Simplify 4k3(3k3 – 5k2 – k + 1) Answer 7k3 – k2 + 3k + 4 12k3 – 20k – 4k + 4 12k6 – 20k5 – 4k4 + 4k3 7k6 – k5 + 3k4 + 4k3

sam (.sam.):

Multiply 4k^(3) by each term inside the parentheses. 12k^(6)-20k^(5)-4k^(4)+4k^(3)

OpenStudy (anonymous):

thanks

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