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Factor completely: 2x3 + 4x2 + 6x + 12
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take x common and you will get an equation(quadratic ) so you can easily solve it...
I have no clue what to do with it
One of your factors will be (x+2). Do you know how to to divide polynomials using long division or synthetic division to find the remaining quadratic equation?
no :(
When I factor out (x-2), I get the quadratic equation:\[2x ^{2}+6\]You will need to use the quadratic formula to solve for the other two factors. quadratic formula \[(-b \pm \sqrt{b ^{2}-4ac})(/2a)\] So a=2 b=0 and c=6
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