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Find two triangles for which A=51 degrees, a = 6.5 ft, and b = 7.9 ft
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i would use law of sines here: \[\frac{\sin B}{7.9} = \frac{\sin 51}{6.5}\] B = 70.83 or 109.17
yay! that's what i got :)
I also found C = 58 degrees but in the book there also another answer to C' which = 20 degrees, I don't get how they got 20 degrees ^^!
I understand B' = 180 - 71 = 109 degrees tho :)
sum of angles is 180 C = 180 - 51 - 70.83 = 58 C = 180 - 51 - 109.17 = 20
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ohhh i see
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