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2reduce 7x-7/4x-4
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Divide both by x-1
is x-1 my answer
no, it isn't
\[{7x-7 \over 4x-4} = {7(x-1) \over 4(x-1)}\]
do i cancell the x-1 and have just 7/4
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got it thanks
2reduce x+4x/4x
It's very similar to the first one, you just have to find a common factor.
thank you got it
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